When both versions run on the same cases, comparing their two pass rates as if they were independent throws information away. Most cases pass on both or fail on both; they say nothing about which version is better. Only the discordant cases count: b cases that passed before and fail now, and c cases that failed before and pass now.
McNemar's test uses just those two numbers:
chi² = (|b − c| − 1)² / (b + c) (with continuity correction) p = erfc( √(chi² / 2) ) (one degree of freedom)
Your task
The new version scored 71% and the old 69% on the same 200 cases. Complete the script, and say whether there is a detectable difference. On submit it also runs on another pair of versions.