Which except block catches a KeyError?

Predict the outputMediumPython only

main.py

try:
    {}["missing"]
except LookupError as e:
    print("lookup:", type(e).__name__)
except KeyError:
    print("key")

try:
    [][3]
except (KeyError, IndexError) as e:
    print("caught", type(e).__name__)

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