A counter built with a closure and nonlocal
Predict the outputMediumPython only
def make_counter():
count = 0
def inc():
nonlocal count
count += 1
return count
return inc
c1 = make_counter()
c2 = make_counter()
print(c1(), c1(), c1())
print(c2())
This question is part of Pro+
Pro+ opens every question in Interview Prep and the mock interview. Every article and the first 2 questions of each topic stay free. Hands-on Selenium and API tasks follow their course lesson's own lock.